Sets: ∈ or ⊆, number sets, ∩ and ∪
By the end: Decide whether a symbol takes or , list the elements of a set, and find and for finite sets and for intervals, endpoints included.
The “element or subset” question was Question 1 in all five sittings we studied, and it is almost always the same test: or ? This lesson secures the first question of the paper.
Understand it
A set is a collection of distinct objects, written between braces: . Order does not matter and repeats do not count, so is the same set as . The objects are the elements.
Two different relations, and the exam tests the difference every time:
- links an element to a set: reads “2 is an element of ”. Its negation is .
- links a set to a set: means every element of is also in .
Read the left side first. A bare element (a number) takes or . Anything in braces takes . The empty set has no elements, and it is a subset of every set, so is always true while is false unless is itself listed in .
Sets are often described by a rule, called set-builder notation. means “all such that ”. Solve the rule first and list the elements: . Only then compare.
Number sets. is the natural numbers (zero is included); (also written ) is without zero; is all integers; is every fraction of two integers with a nonzero denominator; is all real numbers, which also include irrational numbers such as and . Each set sits inside the next, so .
Counting subsets. Each element is either in a subset or out of it, two choices per element, so a set with elements has subsets, counting and the set itself. Leave out the set itself and proper subsets remain; leave out as well and non-empty proper subsets remain.
Intersection and union. keeps only what is in both sets (“and”). collects everything that is in either set (“or”), writing shared elements once.
Intervals. Inequalities are written as intervals. A round bracket leaves the endpoint out and a square bracket keeps it: means . Infinity always gets a round bracket. On a number line, an open circle means “not included” and a filled circle means “included”. Draw both sets on one line, shade where they overlap for , and shade everything covered for .
Essential formulas
See it
Worked examples
Worked example 1
Let . Which statements are true: , , , , , ?
- Solve the rule first: gives or , so .
- is true: 3 is a bare element and it is listed.
- is true: braces on the left take , and the only element of is in .
- and are false: they use the wrong symbol for the left side. A number is not a set, and does not contain the set as an element.
- is true for every set. is false because lists only and .
Answer: True: , , . False: the other three.
Worked example 2
Let and . Find and .
- Write the conditions: is and is .
- For both must hold: and . The left end is open because , and the right end is open because . So .
- For the sets overlap, so they join into one piece from the smallest left end to the largest right end. and , so both ends are included: .
Answer: and .
Worked example 3
Let and . Find and .
- The point belongs to but not to , and every other real number is in exactly one of the two sets.
- Nothing is in both, so .
- Together they cover every real number, so . The shared endpoint 2 is covered by , so the union has no gap.
Answer: and .
Try it yourself
Work it on paper first. Open a hint only when you are stuck, then compare with the solution.
Let and . List , then find and .
Hint 1 of 3
includes . List every natural number below 3.
Hint 2 of 3
For , test each element of against .
Hint 3 of 3
The union keeps ’s element that falls outside as a separate point.
Show the step-by-step solution
- because is a natural number and .
- (it is below 1), while and . So .
- The union is everything in or in : already contains and , and is extra. So .
Answer: , , .
Common mistakes
- Writing or . Look at the left side: a bare element takes , braces take .
- Leaving out of . Zero is a natural number; only and start at 1.
- Saying is true. The empty set is a subset of every set, but it is an element of only if lists it.
- Merging intervals with a gap: is not , because is in neither piece.
- Swapping the symbols: is “and” (the overlap), is “or” (everything covered).
- Counting when the question says non-empty proper subsets. Leave out both and the set itself: .
Exam tips
- Read the left side first. Bare element: or . Braces: . This single habit answers most of Question 1.
- Solve any rule such as and list the elements before you compare anything.
- Draw a number line for every interval question, with open and filled circles. If the options differ only at an endpoint, check just that endpoint.
- To count subsets of a set with elements, start from : subtract 1 for “proper” and 2 for “non-empty proper”.
In short
- is for elements, is for sets; every set.
- includes ; does not.
- An -element set has subsets, proper and non-empty proper.
- is the overlap (and); is everything covered (or).
- Square bracket includes an endpoint, round bracket excludes it; infinity is always round.
Knowledge check
4 questions on this lesson, marked as you go. Take them in ACE CSCA with a free account: passing them completes the lesson, and your progress is saved on every device.
All of Week 1 is free: the eight lessons, the daily questions and the Week 1 test.
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